Saturday, 9 November 2013

1997 HSC - Higher Roots of Complex Numbers

Continuing with our study of roots of complex numbers, this particular question asked for the cube roots of a complex number.  Although the examiner's comments discuss several of the methods attempted by students to solve this one, personally, I think that using polar form (mod-arg)  is by far the easiest and most elegant.  However, as I have said on many occasions, don't let my mathematical "prejudices" influence you!  If you prefer one of the other methods, and can perform the computations correctly, you are at complete liberty to use it!

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